Question

find the product (2x²+3x-7)×(3x²-5x+4)​

Answer 1

Answer:

By using horizontal method,

We have;

(2x2+ 3x – 7) ×(3x2 – 5x + 4)

= 2x2(3x2 – 5x + 4) + 3x(3x2 – 5x + 4) – 7(3x2 – 5x + 4)

= 6x4 – 10x3 + 8x2 + 9x3 – 15x2 + 12x– 21x2 + 35x – 28

Now, putting equal power terms together, we get,

= 6x4 – 10x3 + 9x3 + 8x2 – 15x2– 21x2 + 35x + 12x– 28

= 6x4 – x3 – 28x2 + 47x – 28

Answer 2

your answer is in the above attachment

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