Question

Find the product ( 3√2 - √3 ) ( 4 √3 - √2 ) ​

Answer 1

The product of $(3\sqrt{2} -\sqrt{3} )$ $(4\sqrt{3} -\sqrt{2} )$ is $13\sqrt{6} -18$

Step-by-step explanation:

Given:

$(3\sqrt{2} -\sqrt{3} )$ $(4\sqrt{3} -\sqrt{2} )$

To find:

Product of $(3\sqrt{2} -\sqrt{3} )$ $(4\sqrt{3} -\sqrt{2} )$

Solution:

⇒$(3\sqrt{2} -\sqrt{3} )$ $(4\sqrt{3} -\sqrt{2} )$

⇒$3\sqrt{2}(4\sqrt{3} -\sqrt{2} )-\sqrt{3} (4\sqrt{3} -\sqrt{2} )$

⇒$3$×$4$×$\sqrt{2}$×$\sqrt{3}$$-3(\sqrt{2} )^2-4(\sqrt{3})^2 +\sqrt{3} \sqrt{2}$

⇒$12\sqrt{6} -3(2)-4(3)+\sqrt{6}$

⇒$13\sqrt{6} -6-12$

⇒$13\sqrt{6} -18$

So the final answer is $13\sqrt{6} -18$