find the product:(3x-1)(1-3x)(x-1)
Answers
Answered by
5
Answer:
-(9x³-15x²+7x-1)
Step-by-step explanation:
The product of (3x-1)(1-3x)(x-1)
= [-(3x-1)(3x-1)(x-1)]
= -(3x-1)²(x-1)
= -[(3x)²-2*3x*1+1](x-1)
= -(9x²-6x+1)(x-1)
= -[(9x²-6x+1)x-(9x²-6x+1)1]
= -[9x³-6x²+x-9x²+6x-1]
= -(9x³-15x²+7x-1)
•••♪
Answered by
2
Answer:-(9x³-15x²+7x-1)
Step-by-step explanation:
The product of (3x-1)(1-3x)(x-1)
= [-(3x-1)(3x-1)(x-1)]
= -(3x-1)²(x-1)
= -[(3x)²-2*3x*1+1](x-1)
= -(9x²-6x+1)(x-1)
= -[(9x²-6x+1)x-(9x²-6x+1)1]
= -[9x³-6x²+x-9x²+6x-1]
= -(9x³-15x²+7x-1
Step-by-step explanation:
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