Question

find the product (3x+5)(x-7)​

Answer 1

(3x+5) (x-7)

= 3x(x-7) + 5(x-7)

= 3x² -21x +5x -35

= 3x² - 16x -35

Answer 2

$\large\sf\underline{\underline{\red{Answer}}}:$

$\bf \leadsto 3x^2-16x -35$
$\large\sf\underline{\underline{\red{Solution}}}:$

$\bf :: \implies (3x+5)(x-7)$
$\\\bf ::\implies 3x(x-7)+5(x-7)$
$\\ \bf ::\implies 3x(x)+3x(-7)+5(x)+5(-7)$
$\\ \bf ::\implies 3x^2-21x+5x-35$
$\maltese \color{red}\textbf{Adding like terms}$

$\bf ::\implies 3x^2-16x -35$

$\large\sf Therefore,$
$\sf Answer \:is \:\underline {\pink{3x^2-16x -35}}$