find the product
(3x-5y-4) (9x^2+25y^2+15y+12x-20y+16)
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your answer dear............see attachment
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Putting the value of 3x=a, (-5y)=b and (-4)=c
(3x-5y-4) (9x²+25y²+15xy+12x-20y+16)
=(3x-5y-4) (9x²+25y²+16+15xy-20y+12x)
={(3x)+(-5y)+(-4)}{(3x)²+(-5y)²+(-4)²-(3x)-(-5y)-(-5y)(-4)-(-4)(3x)
=(a+b+c)(a²+b²+c²+ab-bc+ca)
=a³+b³+c³-3abc
=(3a)²m³+(-5y)³+(-4)³-3×(3x)(-5y)(-4)
=27x³-125y³-64-180xy
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