Math, asked by Aaryadesai901234, 5 hours ago

find the product (3x-5y-4)(9x^2 +25y^2 +16+15xy-xy+12x)

Answers

Answered by saravanan04m
1

Step-by-step explanation:

FULL ANSWER WITH STEPS

(3x − 5y — 4) (9x² + 25y² + 15xy + 12x 20y + 16)

= 3x (9x² + 25y² + 15xy + 12x − 20y + 16) — 5y(9x² + 25y² + 15xy + 12x − 20y +

=

16) — 4(9x² + 25y² + 15xy + 12x − 20y + 16)

= 3x9x² + 3x 25y² + 3x * 15xy + 3x *

12x + 3x + (−20y) + 3x + 16 - 5y + 9x² 5у * 25у² - 5у * 15xy - 5у * 12x – 5у *

(-20y) — 5y + 16 – 4 * 9x² 4 * 25y² - 4*

15xy 4 + 12x 4* (-20y) - 4 * 16 -

= 27x³ + 75xy² + 45x²y + 36x² — 60xy + 48x - 45x²y — 125y³ – 75xy² – 60xy +

100y² - 80y - 36x² – 100y² – 60xy − 48x + 80y - 64

= 27x³ + 75xy² - 75xy² + 45x²y — 45x²y +

36x² - 36x² - 60xy - 60xy - 60xy +48x 48x125y³ + 100y² - 100y² - 80y + 80y 64

= 27x³ - 180xy - 125y³ - 64

Here's your answer!

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