find the product (3x+9 )square using the identity
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Answered by
3
Heya !! ☺
As we know, (a+b)² = a²+2ab+b²
So, (3x+9)²
=> 9x²+54x+81
=> x²+6x+9
=> x²+3x+3x+9
=> x(x+3)+3(x+3)
=> (x+3) (x+3)
=> x = -3
As we know, (a+b)² = a²+2ab+b²
So, (3x+9)²
=> 9x²+54x+81
=> x²+6x+9
=> x²+3x+3x+9
=> x(x+3)+3(x+3)
=> (x+3) (x+3)
=> x = -3
Answered by
3
Heya ☺
(3x+9)^2
We use this identity
(a+b)^2 = a^2 + b^2 + 2ab
(3x+9)^2
= (3x)^2 + (9)^2 + 2 × 3x × 9
= 9x^2 + 81 + 54x
Again we use this identity
(a+b)^2 = a^2 + b^2 + 2ab
9x^2 + 81 + 54
= (3x)^2 + (9)^2 + 2 × 3x × 9
= (3x+9) (3x+9)
Thanks
(3x+9)^2
We use this identity
(a+b)^2 = a^2 + b^2 + 2ab
(3x+9)^2
= (3x)^2 + (9)^2 + 2 × 3x × 9
= 9x^2 + 81 + 54x
Again we use this identity
(a+b)^2 = a^2 + b^2 + 2ab
9x^2 + 81 + 54
= (3x)^2 + (9)^2 + 2 × 3x × 9
= (3x+9) (3x+9)
Thanks
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