Question

find the product: (3x+q²)×(2q²-3q²) ​

Answer 1

Answer:

7p²q² - 3q⁴.

Step-by-step explanation:

The expression is: (3p² + q²)(2p² - 3q²)

Compute the product as follows:

\begin{gathered}(3p^{2}+q^{2})(2p^{2}-3q^{2})=3p^{2}(2p^{2}-3q^{2})+q^{2}(2p^{2}-3q^{2})\\=3p^{2}.2p^{2}-3p^{2}.3q^{2}+q^{2}.2p^{2}-q^{2}.3q^{2}\\=6p^{4}-9p^{2}q^{2}+2p^{2}q^{2}-3q^{4}\\=6p^{4}-7p^{2}q^{2}-3q^{4}\\\end{gathered}

(3p

2

+q

2

)(2p

2

−3q

2

)=3p

2

(2p

2

−3q

2

)+q

2

(2p

2

−3q

2

)

=3p

2

.2p

2

−3p

2

.3q

2

+q

2

.2p

2

−q

2

.3q

2

=6p

4

−9p

2

q

2

+2p

2

q

2

−3q

4

=6p

4

−7p

2

q

2

−3q

4

Thus, the product is 6p⁴ - 7p²q² - 3q⁴.

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