Math, asked by sapnanimawat1, 20 days ago

Find the product 3x² (2x - 5) and evaluate it for x = 1​

Answers

Answered by neerasingh1010
0
After solving the equation answer will be 6x3 -15x2
(6*1*1*1)-(15*1*1)
6-15
-9
Answered by divyapakhare468
0

To find : 3x^{2} ( 2x -5  )

Given : x = 1

Solution :

  • Product of 3x^{2} ( 2x -5  )  = 6x^{3} -15x^{2}
  • To find value of expression  3x^{2} ( 2x -5  )  we substitute the value of given of x .  
  • By performing simple subtraction and addition operations we get value .
  • 3x^{2} ( 2x -5  )  

       = 3 (1)^{2} [2 (1 )-5 ] \\= 3 [2-5 ]\\=3(-3 ) \\=-9  

Hence , product is 6x^{3}-15x^{2} and value of expression is -9 .

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