find the product -3y(xy + y ²) and find its value when x =4 and y =5
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Answered by
34
-3y(xy + y^2)
= (-3y)(xy) - (3y)(y^2)
= -3xy^2 - 3y^3
Thus, -3y(xy+y^2) = -3xy^2 - 3y^3
Now, put x = 4 and y = 5
=> -3(4)(5)^2 - 3(5)^3
=> (-3)(4)(25) - (3)(125)
=> - 300 - 375
=> -675
Answered by
1
Answer:
-215
Step-by-step explanation:
-3*4(4*5+(5*5)
-12*20+25
-240+25
-215
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