Question

find the product
(4a-b) and (a-3b)​

Answer 1

Step-by-step explanation:

((3/4)a + (2/3)b) (4a + 3b) Suppose (a – b) and (c – d) are two binomials. By using the distributive law of multiplication over addition twice, we may find their product as given below. (a + b) × (c + d) = a × (c + d) + b × (c + d) = (a × c + a × d) + (b × c + b × d) = ac + ad + bc + bd Let, a= (3/4)a, b=(2/3)b, c= 4a, d= 3b Now, = (3/4)a × (4a + 3b) + (2/3)b × (4a + 3b) = [((3/4)a × 4a) + ((3/4)a + 3b)] – [((2/3)b × 4a) + ((2/3)b × + 3b)] = [3a2 + (9/4)ab + (8/3)ab + 2b2] = [3a2 + ((27+32)/12)ab + 2b2] = [3a2 + (59/12)ab + 2b2]Read more on Sarthaks.com - https://www.sarthaks.com/749116/find-the-product-3-4-a-2-3-b-4a-3b

Answer 2

Answer:

4a (a-3b) -b(a-3b)

4a²-12ab -ab +3b²

4a² -13ab +3b²