Question

find the product (4p^2+5p+7)(3p-7)​

Answer 1

.•♫ SOLUTION ♫•.

• (4p² + 5p + 7)( 3p -7)
• ↬ 4p² ( 3p - 7) +5p ( 3p -7 ) +7 (3p -7 )
• ↬ 12p³ -28p² + 15p² -35p + 21p -49
• ↬ 12p³ - 13p² - 14p - 49

Answer 2

$= (4p^2+5p+7)(3p-7)$

$3p(4p^2+5p+7) - 7(4p^2+5p+7)$

$12 {p}^{3} + 15 {p}^{2} + 21p - {28p}^{2} - 35p - 49$

$= 12 {p}^{3} - 13 {p}^{2} - 14p - 49$