Question

find the product (4p-7)(16p2+28p+49)
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Answer 1

$Product \:of \: (4p-7)(16p2+28p+49)\\= (4p-7)[(4p)^{2} + 4p \times 7 + 7^{2} ] \\= (4p)^{3} - 7^{3}$

/*_______________

By Algebraic Identity :

$\boxed { \pink { (a-b)(a^{2} + ab + b^{2} ) = a^{3} - b^{3} }}$

__________________*/

$= 64p^{3} - 343$

Therefore.,

$\red{Product \:of \: (4p-7)(16p2+28p+49)}$

$\green { = 64p^{3} - 343}$

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