Question

find the product (5-2m) (3+m)​

Answer 1

Answer:

$15 + 1m - 2m^{2}$

Step-by-step explanation:

$(5-2m)(3+m)$

$15 + 5m - 6m - 2m^{2}$

$15 + 1m - 2m^{2}$

Answer 2

Given:

• An equation (5-2m)(3+m)

To Find:

• The product of the given terms.

Solution:

Consider (5-2m)(3+m)

we are going to multiply each term of the first part to the entire second part, we are making use of distributive law.

⇒ 5×(3+m)-2m×(3+m) {multiplying the terms}

⇒ 15+5m-6m-2$m^2$  {subtracting the like terms}

⇒ 15 -m-2$m^2$

⇒ -2$m^2$ -m-15

⇒ 2$m^2$-m-15 {this is in the form of a quadratic equation, a$x^2$+bx-c=0}

∴ The product of (5-2m) (3+m)​ =  2$m^2$-m-15