Question

Find the product (5x²y)×(- 3/5y³z)×(2xz²)Also verify the result for x = 1,
y = -1 and z = 2.​

Answer 1

Answer:

(5x²y)×(-3/5y²z)×(2xz²)=> (5×-3/5×2)×(x²×x)×(y×y²)×(z×z²)

=> 6x³y³z³

therefore, (5x²y)×(-3/5y²z)×(2xz²) = -6x³y³z³...(l)

when x= 1 , y= -1, z = 2 let's verify the equation (l) .

L.H.S => (5×1²×(-1)) × ( -3/5 × (-1)² × 2) (2×1×2²)

=> -5 × (-6/5) × 8 = 48

R.H.S => -6 (1)³ (-1)³ (2)³

=> -6 (1) (-1) (8) = 48

therefore L.H.S = R.H.S

Answer 2

Answer:

Answer:

(5x²y)×(-3/5y²z)×(2xz²)=> (5×-3/5×2)×(x²×x)×(y×y²)×(z×z²)

=> 6x³y³z³

therefore, (5x²y)×(-3/5y²z)×(2xz²) = -6x³y³z³...(l)

when x= 1 , y= -1, z = 2 let's verify the equation (l) .

L.H.S => (5×1²×(-1)) × ( -3/5 × (-1)² × 2) (2×1×2²)

=> -5 × (-6/5) × 8 = 48

R.H.S => -6 (1)³ (-1)³ (2)³

=> -6 (1) (-1) (8) = 48

therefore L.H.S = R.H.S