Math, asked by rajatagal9, 8 hours ago

Find the product: (a^2 + 2b^2) (3a + 5b – 7c)
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Answers

Answered by harshal848
1

Answer:

3a^3 + 5b^3 + 5a^2b - 7a^2c + 6ab^2 - 14b^2c(a^2 + 2b^2)(3a + 5b -7c) \\=> a^2(3a + 5b -7c))  + 2b^2(3a + 5b -7c))\\=> 3a^3 + 5a^2b - 7a^2c   +   6ab^2 + 5b^3 - 14b^2c\\=> 3a^3 + 5b^3 + 5a^2b - 7a^2c + 6ab^2 - 14b^2c

Step-by-step explanation:

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