Question

Find the product:
(a) -2ab, 3ab2 and 4abc​

Answer 1

Answer:

12a3b2c

Step-by-step explanation:

(-4ab) × (-3a2bc) The coefficient of the product of two monomials is equal to the product of their coefficients.

The variable part in the product of two monomials is equal to the product of the variables in the given monomials.

Then, = (-4 × -3) × (a × a2) × (b × b) × c = (12) × (a1+2) × (b1+1) × c … [∵ am × an = am+n] = (12) × (a3) × (b2) × c = 12a3b2c.

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