Math, asked by hari1757, 1 year ago

find the product (a-2b +3c) (ab2-a2b)

Answers

Answered by Arjinderbajwa001

19

(a-2b+3c) (ab2-a2b)

a^2b2-a^2b2-4ab^2+4ab^2+6abc-6abc=0

Answered by apkwer12

43

Answer:

Step-by-step explanation:

= (a-2b+3c) (ab²- a²b)

=a(ab²-a²b) -2b(ab²- a²b) 3c(ab²-=a²b²- a³b - 2ab²+2a²b² +3ab²c -3a²bc

= 3a²b²-a³b-2ab³-3a²bc+3ab²c

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