Find the product and their values for a = -1 , b= 2, c= 1 (4a-2b+3c)(2a-3b)
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8
Answer:
I hope you have got the answer.
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Answered by
1
Step-by-step explanation:
2a(4a-2b+3c)-3b(4a-2b+3c)
8asquare -4ab+6ac-12ab+6bsquare-9bc
8asquare-16ab+6ac+6bsquare-9bc
by putting value
8(-1)square-16(-1)(2)+6(-1)(1)+6(2)square-9(2)(1)
(-8)-(-32)+(-6)+24-18
(-8)-(-32)+(-6)+6
-8-(-32)
-8+32=24
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