Find the product and then evaluate when x=2,y=-1
1- (7x+9y2) (3xy2)
2- -11×(2y5-3/11x2y3)
3- 0.5×(2x2y2+1.5xy3)
please help me
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Answered by
9
Answer:
x = 2 , y = 1
1. (7x + 9y²) (3xy²)
= {7(2) + 9(1)²} {3(2)(1)²}
= (14 + 9)(6)
= 84 + 54
= 138
2. -11 × (2y⁵- 3/11x²y³)
= -11 × {2(1)⁵- 3/11(2)²(1)³}
= -11 × {2 - 3/11(4)}
= -11 × (2 - 12/11)
= -11 × {(22 - 12)/11}
= -11 × 10/11
= -10
3. 0.5 × (2x²y² + 1.5xy³)
= 0.5 × {2(2)²(1)² + 1.5(2)(1)³}
= 0.5 × {2(4) + 3.0}
= 0.5 × (8 + 3.0)
= 0.5 × 11
= 5.5
Answered by
1
Answer:
answer of 1 st question
(7x+9y2) (3xy2)
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