find the product and then evaluate when x =2,y=-1
(b) -11x [2y^5-3/11x^2y^3
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Put x+y=u and xy=v. Then the given equations can be written as
u+v=11,uv=30
∴ u and v are the roots of t2=11t+30=0
Hence u=6,v=5 or u=5,v=6.
Thus x+y=6,xy=5 or x+y=5,xy=6
First we take x+y=6 ..(1)
and xy=5
∴ x and y are the roots of t−6t+5=0
or (t−5)(t−1)=0,
∴t=5,1
Hence x=5,y=1 or x=1,y=5.
We now take x+y=5,xy=6.
Solving these, we shall get t2−5t+6=0
x=3,y=2 or x=2,y=3
Hence the solution set is (5,1),(1,5).(3,2),(2,3).
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