Math, asked by gk552584, 7 hours ago

find the product and verify the result for x 1\2, y = -2 ,z= 1 (5x^2-4x+2)×(3x+y).​

Answers

Answered by gopalpvr
0

Step-by-step explanation:

the product (5x^2-4x+2)×(3x+y)

= 15x^3+5x^2y-12x^2-4xy+6x+2y

verify the result for

x 1\2, y = -2 ,z= 1

= 15(1/2)^3+5(1/2)^2(-2)-12(1/2)^2-4(1/2)(-2)+6(1/2)+2(-2)

=15/8-10/4-3+4+3-4

= -5/8

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