Math, asked by alexa2298, 5 months ago

Find the product and verify the result for x=1 and y=2 of the following .​

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Answers

Answered by Anonymous
2

Answer:

(3x+4y)(3x-4y)(9x2+16y2)

= 3x(3x-4y)+4y(3x-4y)(9x2+16y2)

= 9x2-12xy+12xy-16y2(9x2+16y2)

= (9x2-16y2)(9x2+16y2)

= 9x2(9x2+16y2)-16y2(9x2+16y2)

= 81x4+144x2y2-144x2y2-256y4

= 81x4-256y4

= 81(1)4-256(2)4

= 81-4096

= 4015

Answered by jatt714
0

<body bgcolor=red>4015 answer<marquee direction="up"><font color=yellow>

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