Find the product and verify the result for x=1 and y=2 of the following .
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(3x+4y)(3x-4y)(9x2+16y2)
= 3x(3x-4y)+4y(3x-4y)(9x2+16y2)
= 9x2-12xy+12xy-16y2(9x2+16y2)
= (9x2-16y2)(9x2+16y2)
= 9x2(9x2+16y2)-16y2(9x2+16y2)
= 81x4+144x2y2-144x2y2-256y4
= 81x4-256y4
= 81(1)4-256(2)4
= 81-4096
= 4015
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