Question

Find the product by successive multiplication: (2a_3b),(2a+3b),(2a_3ab+b)​

Answer 1

Answer:

The given polynomials are 2a+3b and 2a−3b we multiply them as follows:

(2a+3b)(2a−3b)=(2a×2a)+(2a×−3b)+(3b×2a)+(3b×−3b)=4a

2

−6ab+6ab−9b

2

=4a

2

−9b

2

Hence, (2a+3b)(2a−3b)=4a

2

−9b

2

.