Science, asked by debnathprasenji5655, 1 year ago

Find the product for CH3CH2 - O - CH2 - CH2 - O - CH2 - C6H5 + HI(excess)

Answers

Answered by Jayagovind

0

Presence of excess of HI favours SN1 mechanism.

So, formation of products is controlled by the stability of the carbocation resulting in the cleavage of C - O bond in protonated ether. Thus the product for given equation are C6H5CH2I, CH3CH2I, HOCH2 - CH2OH.
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