Find the product
I ( 2x+3y) (2x-3y)
II (3x^2+2y^2) (3x^2-2y^2
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First Method
l
(2x+3y) (2x-3y)
=2x (2x-3y)+3y(2x-3y)
=4x²-6xy +6xy -9y²
=4x²-9y²
ll
(3x²+2y²) (3x²-2y²)
=3x²(3x²-2y²)+2y²(3x²-2y²)
=9x⁴-6x²y²+6x²y²-4y⁴
= 9x⁴-4y⁴
Second Method Using Identity
I
(2x+3y) (2x-3y)
= (2x)²-(3y)² [Using identity a²- b² =( a+b)(a-b)]
=4x²-9y²
ll
(3x²+2y²) (3x²-2y²)
= (3x²)²-(2y²)² [Using identity a²- b² =( a+b)(a-b)]
= 9x⁴-4y⁴
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