Math, asked by PragyaTbia, 1 year ago

Find the product, if possible of :  \left[\begin{array}{ccc}2&1&4\\6&-2&3\end{array}\right] \left[\begin{array}{ccc}1\\2\\1\end{array}\right]

Answers

Answered by TooFree
0

Answer:

= \left[\begin{array}{cc}8\\5 \end{array}\right]


Step-by-step explanation:

\left[\begin{array}{ccc}2&1&4\\6&-2&3\end{array}\right] \left[\begin{array}{ccc}1\\2\\1\end{array}\right]

= \left[\begin{array}{cc}2 \times 1 + 1 \times 2 + 4 \times 1\\6 \times 1 + (-2) \times 2 + 3 \times 1\end{array}\right]

= \left[\begin{array}{cc}2+ 2 + 4\\6 -4 + 3 \end{array}\right]

= \left[\begin{array}{cc}8\\5 \end{array}\right]

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