find the product in given attachment.
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(i) (a2 ) × (2a22 ) × (4a26 )
= 2 × 4 × a2 × a22 × a26
= 8a50 [According to exponent rules, am × an = am + n]
(ii) (2/3 xy) × ( -9/10 x2 y2 )
= (2/3) × (-9/10) × x × y × x2 × y2
= -3/5 x3 y3 [Since, am × an = am + n]
(iii) (-10/3 pq3) × (6/5 p3q)
= -10/3 × 6/5 × p × q3 × p3 × q
= - 4 p4q4 [Since, am × an = am + n]
(iv) x × x2 × x3 × x = x10 [Since, am × an = am + n]
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here is your answer
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