Math, asked by nagragurpreet822, 10 hours ago

find the product in given attachment. ​

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Answered by мααɴѕí
4

Answer:

(i) (a2 ) × (2a22 ) × (4a26 )

= 2 × 4 × a2 × a22 × a26

= 8a50 [According to exponent rules, am × an = am + n]

(ii) (2/3 xy) × ( -9/10 x2 y2 )

= (2/3) × (-9/10) × x × y × x2 × y2

= -3/5 x3 y3 [Since, am × an = am + n]

(iii) (-10/3 pq3) × (6/5 p3q)

= -10/3 × 6/5 × p × q3 × p3 × q

= - 4 p4q4 [Since, am × an = am + n]

(iv) x × x2 × x3 × x = x10 [Since, am × an = am + n]

Answered by johandamian776
5

Answer:

here is your answer

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