Question

Find the product of 0.2xy(3x+2y) and verify the result when x=5 and y= -1.

Answer 1

The product for the given expression is $0.2xy(3x+2y)=0.6x^2y+0.4xy^2$

The result $0.6x^2y+0.4xy^2$ when x=5 and y=-1 is -13

Step-by-step explanation:

Given expression is 0.2xy(3x+2y)

To find the given product of the expression and verify the result when x=5 and y=-1 :

• 0.2xy(3x+2y)
• =0.2xy(3x)+0.2xy(2y)
• $=0.6x^2y+0.4xy^2$
• Therefore 0.2xy(3x+2y)$=0.6x^2y+0.4xy^2$

The product for the given expression is $0.2xy(3x+2y)=0.6x^2y+0.4xy^2$

Now verify the result when x=5 and y=-1 :

• $0.6x^2y+0.4xy^2$
• Put x=5 and y=-1 in the above expression we get
• $=0.6(5)^2(-1)+0.4(5)(-1)^2$
• $=-0.6(25)+0.4(5)$
• $=-15+2$
• $=-13$

The result $0.6x^2y+0.4xy^2$ when x=5 and y=-1 is -13

Answer 2

Answer:

The product for the given expression is 0.2xy(3x+2y)=0.6x^2y+0.4xy^20.2xy(3x+2y)=0.6x

2

y+0.4xy

2

The result 0.6x^2y+0.4xy^20.6x

2

y+0.4xy

2

when x=5 and y=-1 is -13

Step-by-step explanation:

Given expression is 0.2xy(3x+2y)

To find the given product of the expression and verify the result when x=5 and y=-1 :

0.2xy(3x+2y)

=0.2xy(3x)+0.2xy(2y)

=0.6x^2y+0.4xy^2=0.6x

2

y+0.4xy

2

Therefore 0.2xy(3x+2y)=0.6x^2y+0.4xy^2=0.6x

2

y+0.4xy

2

The product for the given expression is 0.2xy(3x+2y)=0.6x^2y+0.4xy^20.2xy(3x+2y)=0.6x

2

y+0.4xy

2

Now verify the result when x=5 and y=-1 :

0.6x^2y+0.4xy^20.6x

2

y+0.4xy

2

Put x=5 and y=-1 in the above expression we get

=0.6(5)^2(-1)+0.4(5)(-1)^2=0.6(5)

2

(−1)+0.4(5)(−1)

2

=-0.6(25)+0.4(5)=−0.6(25)+0.4(5)

=-15+2=−15+2

=-13=−13

The result 0.6x^2y+0.4xy^20.6x

2

y+0.4xy

2

when x=5 and y=-1 is -13