Question

find the product of.
1). 104²
2). (2x+3)(3x-2)
3). (xy+3)(xy-5)
​

Answer 1

Step-by-step explanation:

Q). (104)²

(104)² is written as (100+4)²

Using identity (a+b)² = a²+2ab+b²

(104)² = (100+4)²

= (100)²+2(100)(4)+(4)²

= 10000+2(400)+16

= 10000+800+16

= 10816 Ans.

Q). (2x+3)(3x-2)

Using identity (x+a)(x-b) = x²+(a-b)x-ab

=> x²+(3-2)x-3×2

=> x²+(1)x-6

=> x²+x-6 Ans.

Q). (xy+3)(xy-5)

=> (xy)²+{3+(-5)}(3x)+(3)(-5)

=> x²y²+(3-5)(3x)-15

=> x²y²-2x-15 Ans

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