Question

Find the product of (1/2x³)(-10x)(1/5x²) and verify the results for x=1
Please try to do it on a paper with pen and then post the answer...& pls no spam

Answer 1

Answer:

$\red {\left(\frac{1}{2x^{3}}\right) (-10x) \left( \frac{1}{5x^{2}}\right)} \green {= \frac{-1}{x^{4}}}$

Step-by-step explanation:

$\left(\frac{1}{2x^{3}}\right) (-10x) \left( \frac{1}{5x^{2}}\right)$

$= \left( \frac{-10x}{2x^{3}\times 5x^{2}}\right)\\= \left( \frac{-10x}{10x^{3+2}}\right) \\= \frac{ -1}{x^{5-1}}\\= \frac{-1}{x^{4}}$

Therefore.,

$\red {\left(\frac{1}{2x^{3}}\right) (-10x) \left( \frac{1}{5x^{2}}\right)} \green {= \frac{-1}{x^{4}}}$

/* Substitute x = 1 in above equation , we get

$LHS = \left(\frac{1}{2\times 1^{3}}\right) (-10\times 1) \left( \frac{1}{5\times 1^{2}}\right)\\= -1$

$RHS = \frac{ -1}{1^{4}} = -1$

$LHS = RHS$

•••♪

Answer 2

Answer:

x=1

1/2x^3=1/2*(1)^3

=1/2*1*1*1=1/2

-10x = -10*1 = -10

1/5x^2=1/5*(1)^2 = 1/5*1*1 = 1/5

1/2* -10 * 1/5 = -1