Question

find the product of (1/2x3)(-10x)(1/5x2)verify the result for x=1​

Answer 1

$(\frac{1}{2}x^3)(-10x)(\frac{1}{5}x^2)=-x^6$

Step-by-step explanation:

Given : Expression $(\frac{1}{2}x^3)(-10x)(\frac{1}{5}x^2)$

To find : The product of the expression ?

Solution :

Expression $(\frac{1}{2}x^3)(-10x)(\frac{1}{5}x^2)$

Product of first two terms,

$(\frac{1}{2}x^3)(-10x)(\frac{1}{5}x^2)=(-5x^4)(\frac{1}{5}x^2)$

Product of rest terms,

$(\frac{1}{2}x^3)(-10x)(\frac{1}{5}x^2)=-x^6$

Check for x=1,

Take LHS,

$LHS=(\frac{1}{2}x^3)(-10x)(\frac{1}{5}x^2)$

$LHS=(\frac{1}{2}(1)^3)(-10(1))(\frac{1}{5}(1)^2)$

$LHS=\frac{1}{2}\times -10\times \frac{1}{5}$

$LHS=-1$

Taking RHS,

$RHS=-x^6$

$RHS=-(1)^6$

$RHS=-1$

LHS=RHS

#Learn more

Find the products (x+2)(x-2)​

https://brainly.in/question/11416122

Answer 2

Answer:

answer is this

Step-by-step explanation:

(a)(-10x)(}x²)

Product of first two terms,

(호교3) (-10z)(금교2) = (-5x4)(}x2)

Product of rest terms,

(ža³)(-10x)(}x²2) = -x6

Check for x=1,

Take LHS,

LHS = (}æ³)(-10x)(}a²)

LHS =(}(1)³)(-10(1))(}(1)²)

LHS = 1 x -10 ×

LHS = -1

Taking RHS

RHS = -x6

RHS=-(1)6 =

RHS = -1

LHS=RHS

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