Find the product of 1 +3√2 and 1-3√2.
Is this product rational irrational ?
Answers
Answered by
29
Answer:
Here is the answer =>
Step-by-step explanation:
(1+3√2)*(1-3√2)
So let 1 be ‘a’ and 3√2 be ‘b’.
Now (a+b)(a-b) => a^2-b^2
SUBSTITITING THE VALUES =>
(1+3√2)(1-3√2)
=>(1)^2-(3√2)^2
=>1-9(2)
=>1-18
=>-17.
Yes the product is a rational number => -17.
So -17 is the product of (1+3√2)(1-3√2) which is the required answer.
HOPE IT HELPS.
Answered by
4
Answer:
Step-by-step explanation:
tep-by-step explanation:
(1+3√2)*(1-3√2)
So let 1 be ‘a’ and 3√2 be ‘b’.
Now (a+b)(a-b) => a^2-b^2
SUBSTITITING THE VALUES =>
(1+3√2)(1-3√2)
=>(1)^2-(3√2)^2
=>1-9(2)
=>1-18
=>-17.
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