find the product of 1+3 √2 and 1-3 √2.is this producta a rational or irrational?
Answers
Answered by
0
Answer:
Rational
Step-by-step explanation:
( 1 + 3√2 )( 1 - 3√2 )
(1)^2 - (3 √2)^2 [ (a+b)(a-b) = a^2 - b^2 ]
1 - (9*2)
1 - 18
-17
-17 is a rational no.
therefore product of the 1+3 √2 and 1-3 √2 is rational no.
Answered by
0
Answer:
Rational
Step-by-step explanation:
( 1 + 3√2 )( 1 - 3√2 )
(1)^2 - (3 √2)^2 [ (a+b)(a-b) = a^2 - b^2 ]
1 - (9*2)
1 - 18
-17
-17 is a rational no.
therefore product of the 1+3 √2 and 1-3 √2 is rational no.
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