Question

find the product of 1+3 √2 and 1+3 √2is this product a rational of irrational​

Answer 1

Answer:

$19+6\sqrt{2}$

Step-by-step explanation:

$(1+3\sqrt{2} )(1+3\sqrt{2} )$

$(1+3\sqrt{2} )^{2}$

Using:

$(a+b)^{2} =a^2+b^2+2ab$

$(1)^2+(3\sqrt{2} )^2+2(1)(3\sqrt{2} )$

$1+18+6\sqrt{2}$

$19+6\sqrt{2}$

Hope it helps