Question

find the product of 103×98 using the identity​

Answer 1

$\huge \pink{Aŋʂῳɛཞ{ \implies}}$

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103 * 98 = (100 + 3) (100 -2 ) = 100² + 3*100  - 100 * 2 - 3 * 2

     = 10000 + 300 -200- 6

   = 10094

we use identity : (A+B)(A-C) = A^2 + AB - AC - BC

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103 * 98 = (102 + 1) * 98 = 102 * 98 + 98

       = (100 + 2) (100 -2 )  + 98

       = 100² - 2² + 98

         = 10094

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