Question

find the product of 10x ka square, -16x ka cube​

Answer 1

Answer:

Hey there

$= {(10x)}^{2} \times { ( - 16x)}^{3} \\ = - 100 {x}^{2} \times 4096 {x}^{3} \\ = - 409600 {x}^{5}$

Hope it helps you

Please mark it as branliest

Answer 2

Answer:

The value of (10x)² × (-16x)³ is -409600 x⁵.

Step-by-step explanation:

Exponent rule:

$a^{m}\times a^{n}=a^{m+n}$

Compute the value of (10x)² × (-16x)³ as follows:

$(10x)^{2}\times(-16x)^{3}=10^{2}\times x^{2}\times(-16)^{3}\times x^{3}\\=100\times x^{2}\times-4096\times x^{3}\\=-409600x^{2+3}\\=-409600x^{5}$

Thus, the value of (10x)² × (-16x)³ is -409600 x⁵.