find the product of 2/3 a2 (3b2-9ab)
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Answer:
2a^2b^2 - 6a^3b
Step-by-step explanation:
(2/3)a^2(3b^2-9ab)
= (2/3)*(3)*(a^2 * b^2) - (2/3)*(9)*(a^2 * ab)
= 2a^2b^2 - 6a^3b
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