Question

find the product of 2/3 xyz * 3/4x^2y^2z^2 * 2/ x^3y^3z^3​

Answer 1

Answer:

(4x−2y−3z)

2

We know that (x+y+z)

2

=x

2

+y

2

+z

2

+2xy+2yz+2xz

Here x=4x, y=-2y and z=-3z we get

(4x−2y−3z)

2

=(4x)

2

+(−2y)

2

+(−3z)

2

+2(4x)(−2y)+2(−2y)(−3z)+2(4x)(−3z)

=16x

2

+4y

2

+9z

2

−16xy+12xy−24xz

Step-by-step explanation:

hope i help you so much