find the product of 2/7 x square(7y + 14x) and verify the result when x= 2 and y =3.
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Given: The term 2/7 x² ( 7y + 14x )
To find: the product and verify the result when x= 2 and y =3.
Solution:
- Now we have given 2/7 x² ( 7y + 14x )
(2/7 x² × 7y) + (2/7x² × 14x)
2x²y + 4x³
- Putting x = 2 and y = 3, we get:
2x²y + 4x^3
= (2x2x2x3) + (4x2x2x2)
= 24 + 32
= 56
Answer:
So the value of given term when x= 2 and y =3 is 56.
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