Math, asked by ananychhabra2112, 7 months ago

find the product of 2/7 x2 ( 7 y + 14 X ) verify when result is X= 2 y= 3​

Answers

Answered by AvengerSetu
2

Answer:

2x²y + 4x³

Step-by-step explanation:

2/7 x² ( 7y + 14x )

= (2/7 x² * 7y) + (2/7x² * 14x)

=   2x²y + 4x³

verification when x= 2 and y = 3.

L.H.S :

(2/7 x² * 7y) + (2/7x² * 14x)

(2/7 * 2 *2 *7* 3 ) + (2/7 * 2 * 2 * 14 * 2)

= (8/7*21)+(8/7*28)

=(8*3)+(8*4)

= 24 + 32 = 56

R.H.S:

2x²y + 4x^3

= (2* 2 *2 * 3) + (4 * 2 * 2 *2)

= 24 + 32

= 56

Therefore L.H.S = R.H.S

Verified

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Answered by pritamjanasdpl05
1

Answer:

28

Step-by-step explanation:

2/7×2(7×3+14×2)

2/7×2(21+28)

2/7×2(49)

2/7×98

2×14

28

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