Find the product of 2 numbers such that their sum multiplied by the sum of their squares is 5500 and their difference multiplied by the difference of their squares is 352.
Answers
Step-by-step explanation:
Let x and y = the numbers
(x+y)(x2+y2)=5500(x+y)(x2+y2)=5500 ← Equation (1)
(x−y)(x2−y2)=352(x−y)(x2−y2)=352 ← Equation (2)
(x+y)(x2+y2)(x−y)(x2−y2)=5500352(x+y)(x2+y2)(x−y)(x2−y2)=5500352
(x+y)(x2+y2)(x−y)(x−y)(x+y)=1258(x+y)(x2+y2)(x−y)(x−y)(x+y)=1258
x2+y2(x−y)2=1258x2+y2(x−y)2=1258
8x2+8y2=125(x2−2xy+y2)8x2+8y2=125(x2−2xy+y2)
117x2−150xy+117y2=0117x2−150xy+117y2=0
(13x−9y)(9x−13y)=0(13x−9y)(9x−13y)=0
For 13x - 9y = 0
y=139xy=139x ← Equation (3)
From Equation (2)
(x−139x)[x2−(139x)2]=352(x−139x)[x2−(139x)2]=352
(−49x)(−8881x2)=352(−49x)(−8881x2)=352
(−49x)(−8881x2)=352(−49x)(−8881x2)=352
352729x3=352352729x3=352
x3=729x3=729
x=9x=9 answer
From Equation (3)
y=139(9)y=139(9)
y=13y=13
Answer:
(a+b)(a^2+b^2)=5500
(a-b)(a^2-b^2)=352
(a-b)^2(a+b)=352
Then:
5500/(a^2-b^2)=352/(a-b)^2
Then(a-b)^2 must be a factor of 352
So,
(a-b)^2=4 or (a-b)^2=16
But it can't be 4,(a-b)^2=16
Then:a^2 +b^2=250
(a-b)=4
So,the solution is a=13 and b=9.
Hope it helps,
Step-by-step explanation:
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