Find the product of (2a-3)(2a-3) using identities
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Answer:
4a²-12a+9
Step-by-step explanation:
(2a-3) (2a-3)=(2a-3)²
(2a-3)² = (a-b)²
(a-b)²=a²-2ab+b²
a=2a
b=3
substituting in identity:-
(2a)²-2 x(2a)x(3)+(3)² [a²-2ab+b²]
= 4a²-12a+9
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