find the product of (2a+3x) and (2x+3b)
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The given polynomials are 2a+3b and 2a−3b we multiply them as follows:
(2a+3b)(2a−3b)=(2a×2a)+(2a×−3b)+(3b×2a)+(3b×−3b)=4a
2
−6ab+6ab−9b
2
=4a
2
−9b
2
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Answer:
2a(2x+3b)+3x (2x+3b) = 4ax+6ab+6(x)2 +9xb
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