Question

Find the product of (2a–b + 3c)( 4a^2+b^2+ 9c^2+ 2ab + 3bc –6ca )

Answer 1

Answer:

8a3−27b3−8c3−36abc

Step-by-step explanation:

[2a+(−3b)+(−2c)][(2a)2+(−3b)2+(−2c)2−2a×(−3b)−(−3b)(−2c)−(2a)(−2c)]  

(x+y+z)(x2+y2+z2−xy−yz−zx) (wherex=2a,y=−3b andz=−2c)

=x3+y3+z3+3xyz=(2a)3+(−3b)3+(−2c)3−3×2a×(−3b)×(−2c)

=8a3−27b3−8c3−36abc