Question

Find the product of (2a–b + 3c)( 4a^2+b^2+ 9c^2+ 2ab + 3bc –6ca )

Answer 1

Answer:

[2a+(-3b)+(-2c)][(2a)2+(-3b)2+(-2c)2-2a×(-3b)-(-3b)(-2c)-(2a)(-2c)]

2a+(-3b)+(-2c)][(2a)2+(-3b)2+(-2c)2-2a×(-3b)-(-3b)(-2c)-(2a)(-2c)](x+y+z)(x2+y2+z2-xy-yz-zx)(wherex=2a,y=-3bandz=-2c)

2a+(-3b)+(-2c)][(2a)2+(-3b)2+(-2c)2-2a×(-3b)-(-3b)(-2c)-(2a)(-2c)](x+y+z)(x2+y2+z2-xy-yz-zx)(wherex=2a,y=-3bandz=-2c)=x3+y3+z3+3xyz=(2a)3+(-3b)3+(-2c)3-3×2a×(-3b)×(-2c)

Step-by-step explanation:

may this answer help you!^_^