Question

Find the product of (2b+a)(2b-a)(4b^2+a^)​

Answer 1

Answer:

Step-by-step explanation:

HEY HERE IS YOUR ANSWER ☺☺☺

We can easily find the resulting product by using identity (a + b) (a - b) = a^2 - b^2

But remember we will solve it step by step from the first one to last one .

First one (a - 2b) (a + 2b)

Identity used = (a + b) (a - b) = a^2 - b^2

where a = a and b = 2b.

Second binomial = (a^2 +4b^2)

Result from first product = (a^2 - 4b^2)

We can easily find their product by using the first identity (a + b) (a - b) = a^2 - b^2.

Where a = a^2 and b = 4b^2.

Third binomial =( a^4 + 16b^4)

Result from second product = (a^4 - 16b^4)

We can easily find the resulting product by using identity (a + b) ( a - b) = a^2 - b^2

where a = a^4 and b = 16b^4

So the resulting product is:- a^8 - 256b^8

HOPE MY ANSWER HELPED☺☺☺

#AADI 93