find the product of (2x-1)(3x²-2x-2)
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Answered by
4
the product of (2x-2)(3x^2 -2x-2)
= 2x(3x^2-2x-2) -1(3x^2-2x-2)
=6x^3 -4x^2 -4x -3x^2 +2x +2
=6x^3 -7x^2 -2x +2.
= 2x(3x^2-2x-2) -1(3x^2-2x-2)
=6x^3 -4x^2 -4x -3x^2 +2x +2
=6x^3 -7x^2 -2x +2.
subhashree5:
u should chek ur ans clearly
-4x^2-3x^2=7x^2
its 4x^2 -3x^2
not -4x^2 -3x^2
sry i hot it
i was wrnf
wrng
Answered by
6
(2x-1)(3x^2-2x-2)
=2x (3x^2-2x-2)-1 (3x^2-2x-2)
6x^3-4x^2-4x-3x^2-2x-2
=6x^3-4x^2-4x-3x^2+2x+2
=6x^3-7x^2-2x+2
=2x (3x^2-2x-2)-1 (3x^2-2x-2)
6x^3-4x^2-4x-3x^2-2x-2
=6x^3-4x^2-4x-3x^2+2x+2
=6x^3-7x^2-2x+2
its wrong
ohk tell my mistake
thanks for correcting
ur welcome
so 1st see on u then others
ohk
sry
its ok
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