Question

Find the product of;(2x+3y+4z) (4x^2+9y^2+16z^2-6xy-12yz-8zx) ​

Answer 1

Answer:

(2x+3y+4z)(4x²+9y²+16z²-6xy-12yz-8zx).

(2x+3y+4z)((2x)²+(3y)²+(4z)²-(2x)(3y)-(3y)(4z)-(4z)(2x)).

It is in the form of (a+b+c)(a²+b²+c²-ab-bc-ca)=a³+b³+c³-3abc where a=2x, b=3y & c=4z.

(2x+3y+4z)((2x)²+(3y)²+(4z)²-(2x)(3y)-(3y)(4z)-(4z)(2x))=(2x)³+(3y)³+(4z)³-3(2x)(3y)(4z).

(2x+3y+4z)((2x)²+(3y)²+(4z)²-(2x)(3y)-(3y)(4z)-(4z)(2x))=8x³+27y³+64z³-72xyz.

I think this is your answer.