Question

Find the product of (2x-3y) and (-3xy² + 4y²) and hence find the value of the polynomial at x= 3 and y= -2.

Pls answer this correctly ​

Answer 1

Answer:

-240

Step-by-step explanation:

(2x-3y)*(-3xy^2+4y^2)

= -6x^2y^2+8xy^2+9xy^3-12y^3

Now putting x=3 and y= -2 we get,

= -6*3^2*(-2)^2+8*3*(-2)^2+9*3*(-2)^3-12*(-2)^3

= -6*9*4+8*3*4+9*3*(-8)-12*(-8)

= -240